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檔名；submit.php
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=big5">
<title>PHP提交表單</title>
<style type="text/css">
<!--
h1,h2,h3,h4,h5,h6 {
font-family: PHP提交表單;
}
-->
</style></head>
<body>
<H1 align=center>多重次分頁</H1>
<TABLE align=center width=740 border=1>
<TR>
<TD>
<form name="forml" method="get" action="Ssubmit.php">
<TABLE align=center width=800 border=1>
<tr><td>檔案數量 <td><input type="text" name="textField" id="a1"></tr>
<tr><td> <td><input type="submit" name="Submit" value="Sumit"></tr>
</form>
<form name="forml" method="post" action="upside.php">
<?php
$c=0;
$c++;
for ($i=0;$i<$_GET['textField'];$i++){
echo "<input type='Hidden' name='abc' value='$i'>";
echo "<tr><td>檔案名稱<td><input type='text' name='filename$i'></tr>";
echo "<td> 檔案路徑<td><input type='text' name='road$i'>";
}?>
<tr><td> <td><input type="submit" name="Submit" value="Sumit"></tr>
</form>
</TABLE>
</TD>
</TR>
</TABLE>
</FORM>
</body>
</html>
收的檔名；upside.php
接<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=big5">
<title>UP</title>
<SCRIPT Language="JavaScript">
<!--
function GO()
{location.href="http://www.pili.com.tw"/;}
//-->
</SCRIPT>
</head>
<body>
<div id="menu">
<li><a href="接收submit.php檔內的$road的網址字串" target="DOWN">GOOGL</a></li>
<li><a href="接收submit.php檔內的$road的網址字串" target="DOWN">Yahoo</a></li>
<li><a href="接收submit.php檔內的$road的網址字串" target="DOWN">GAMER</a></li>
<li><a href="接收submit.php檔內的$road的網址字串" target="DOWN">PLIL</a></li>
<FRAME SRC="downside.html" NAME="DOWN"></iframe>
</div>
</body>
</html>
請問各位高手我應該如何去接收submit.php所送出的字串送到upside.php檔中，做超連結使用ㄋ???
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